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-1=3x^2+10x+7
We move all terms to the left:
-1-(3x^2+10x+7)=0
We get rid of parentheses
-3x^2-10x-7-1=0
We add all the numbers together, and all the variables
-3x^2-10x-8=0
a = -3; b = -10; c = -8;
Δ = b2-4ac
Δ = -102-4·(-3)·(-8)
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4}=2$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-2}{2*-3}=\frac{8}{-6} =-1+1/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+2}{2*-3}=\frac{12}{-6} =-2 $
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